Eigenvector from Eigenvalues

It is proved that Where is an matrix, is the element of the eigenvector of , is the cofactor of .

Proof

Consider the adjugate matrix of , i.e.


Lemma 1 Proof We consider replace the column of with its column, which generates , then we have Applying the identity to , we obtain The proof is exactly the same for .


The spectral decomposition for gives , where are orthonormal vectors. Then Notice that where Substitute in we obtain Hence, is the eigenvalue that corresponds to of . Likewise, we apply spectral decomposition to , we obtain As are the roots to 's characteristic equation, then . We have Take , then all the term including will be eliminated. That is Then we extract the column and row on the both hand sides, then we obtain The simplified form yields